CGAL users discussion list

[Guillaume Damiand <>]

If you test, you will see that it is important...

I havent test your idea yet, but i think it is not important for compiler that initialization is in or out of for loop because the compiler translate the statement (CGAL::Random random) only one time.

 

 

 

--- On Wed, 6/22/11, Doug Epps wrote:

From: Doug Epps
Subject: Re: [cgal-discuss] CGAL::Random
To:
Date: Wednesday, June 22, 2011, 5:04 AM

I believe (though i can't compile it right now) what Sylvain meant was to do:

CGAL::Random random;
for (int t = 1; t<4; t++)
{   
    double randi=random.get_double (0.0, 1);
    std::cout << "randi" << randi << std::endl;
}

Note how the CGAL::Random is OUTSIDE the loop, and so is in scope for all 3 iterations of the loop, rather than being created for each one.

My intuition is that the creation of the CGAL::Random object seeds the random-number generator.
So you're getting the same thing over and over.


On Jun 21, 2011, at 9:50 PM, sara Samadi wrote:

>  for (int t=1; t<4; t++)
> > {
> > CGAL::Random random;
> > double randi=random.get_double (0.0, 1);
> > double mandi=random.get_double (0.0, 1);
> > std::cout<<"randi="<<randi<<std::endl;
> > std::cout<<"mandi="<<mandi<<std::endl;
> > }


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