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- From: StevenChen06 <>
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- Subject: [cgal-discuss] Re: On results of 2D Triangulation
- Date: Mon, 21 May 2012 03:06:55 -0700 (PDT)
http://cgal-discuss.949826.n4.nabble.com/file/n4647926/example.png
Take this for example.
The left graph is generated by 2D triangulation. The horizontal edge is
shared by 3 triangles.
The right one is what we need. There is no edge shared by more than 2
triangles.
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Sent from the cgal-discuss mailing list archive at Nabble.com.
- [cgal-discuss] On results of 2D Triangulation, StevenChen06, 05/21/2012
- Re: [cgal-discuss] On results of 2D Triangulation, Jakob van Bethlehem, 05/21/2012
- [cgal-discuss] Re: On results of 2D Triangulation, StevenChen06, 05/21/2012
- Re: [cgal-discuss] Re: On results of 2D Triangulation, Olivier Devillers, 05/21/2012
- [cgal-discuss] Re: On results of 2D Triangulation, StevenChen06, 05/21/2012
- Re: [cgal-discuss] On results of 2D Triangulation, Jakob van Bethlehem, 05/21/2012
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