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- From: Pierre Casteran <pierre.casteran AT labri.fr>
- To: coq-club AT pauillac.inria.fr
- Subject: [Coq-Club] well ordered sets and least elements
- Date: Sun, 1 May 2005 15:34:50 +0200
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
Hello,
I suspect thet the statement "Every (recursive, non empty) subset
of a well ordered set has a least element" cannot be intuitionnistically
proven. All the proofs I know use classically the impossibility of
building an infinite decreasing sequence. On the other side, I couldn't
find any algorithm for finding such an element, starting from the
non-emptyness witness.
Is that true?
It is is, where can I find a formal argument (e.g. reduction to a
known problem) ?
Thenks in advance,
Pierre
--
Pierre Casteran
http://www.labri.fr/Perso/~casteran/
(+33) 540006931
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- [Coq-Club] well ordered sets and least elements, Pierre Casteran
- Re: [Coq-Club] well ordered sets and least elements, Pierre Casteran
- Re: [Coq-Club] well ordered sets and least elements, Bas Spitters
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