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- From: vsiles AT lix.polytechnique.fr
- To: "Keiko Nakata" <keiko AT kurims.kyoto-u.ac.jp>
- Cc: coq-club AT pauillac.inria.fr
- Subject: Re: [Coq-Club] Can Qed raise a type error?
- Date: Wed, 9 Jul 2008 10:24:47 +0200 (CEST)
- Importance: Normal
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
Hi,
by using the tactic "fix" without being cautious, you can complete a proof
but the Qed failed, mostly because your recursive call was not on a sub
term.
That's the only case I know where Qed can failed.
I hope it'll help a little.
Vincent
> Hello.
>
> Is it possible that "Qed" ends up with a type error,
> or other serious errors except for the out of memory?
> I never omit to instantiate existential variables,
> no metavariables are left (e.g. no eauto or eapply),
> or I do not use co-induction.
>
> Currently I do not want to struggle with the out of memory problem
> which I incur by Qed, but I want to be sure my proof term is correct.
>
> With best regards,
> Keiko
>
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- [Coq-Club] Can Qed raise a type error?, Keiko Nakata
- Re: [Coq-Club] Can Qed raise a type error?, vsiles
- Re: [Coq-Club] Can Qed raise a type error?,
Keiko Nakata
- Re: [Coq-Club] Can Qed raise a type error?,
Julien Forest
- [Coq-Club] Naming a term vs. using the term directly., Razvan Voicu
- Re: [Coq-Club] Can Qed raise a type error?, Xavier Leroy
- Message not available
- Re: [Coq-Club] Can Qed raise a type error?, Keiko Nakata
- Re: [Coq-Club] Can Qed raise a type error?,
Julien Forest
- Re: [Coq-Club] Can Qed raise a type error?,
Keiko Nakata
- Re: [Coq-Club] Can Qed raise a type error?, vsiles
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