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- From: frederic.blanqui AT inria.fr
- To: Pierre Casteran <pierre.casteran AT labri.fr>
- Cc: roconnor AT theorem.ca, Coq Club <coq-club AT pauillac.inria.fr>, sebastien.hinderer AT loria.fr
- Subject: Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2.
- Date: Fri, 19 Sep 2008 13:30:35 +0200 (CEST)
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
On Fri, 19 Sep 2008, Pierre Casteran wrote:
Isn't there a hidden axiom if you use eq_dep_eq ?
I don't think so since it takes as argument a proof that eq_nat is decidable.
- [Coq-Club] forall n m (H1 H2:le n m), H1=H2., roconnor
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2.,
Frederic Blanqui
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2.,
Pierre Casteran
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2., frederic . blanqui
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2., Sébastien Hinderer
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2., Hugo Herbelin
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2.,
Pierre Casteran
- Re: [Coq-Club] forall n m (H1 H2:le n m), H1=H2.,
Frederic Blanqui
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