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- From: Ben Horsfall <ben.horsfall AT gmail.com>
- To: Coq Club <coq-club AT inria.fr>
- Subject: [Coq-Club] Rewriting with mixed Equivalence relations
- Date: Thu, 24 Nov 2011 17:39:41 +1100
Suppose that I have Equivalence instances for two types A and B (arising from
PartialOrder instances), and I have a function f : A -> B. I would like to be
able to use rewriting in a situation like this:
Lemma example : forall {A B}
{eqA RA : relation A} `{PartialOrder A eqA RA}
{eqB RB : relation B} `{PartialOrder B eqB RB}
(f : A -> B), forall x y, x === y -> f x === f y.
Proof. intros. rewrite H1. reflexivity. Qed.
(=== is overloaded notation for eqA and eqB.) But the rewrite step fails to
rewrite the goal (to f y === f y), with missing rewriting constraints. What
is required (mathematically and technically) to get this kind of example to
work, i.e. to get eqB (or RB for that matter) to respect eqA in the
appropriate way?
Ben
- [Coq-Club] Rewriting with mixed Equivalence relations, Ben Horsfall
- Re: [Coq-Club] Rewriting with mixed Equivalence relations, Matthieu Sozeau
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