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[Coq-Club] Equality of "sig" types


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  • From: Helge Bahmann <hcb AT chaoticmind.net>
  • To: coq-club AT inria.fr
  • Subject: [Coq-Club] Equality of "sig" types
  • Date: Fri, 29 Jun 2012 10:06:35 +0200

Hello,

I am stuck in a proof with the goal "exist P a prf_a = exist P b prf_b" with
the assumption "a = b" available -- I have read about dependent pairs, but I
have been unable to figure out how to apply this syntactically to my problem
(if it applies at all?).

Could anyone give me a hint how I could proceed?

Regards
Helge



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