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- From: Adam Chlipala <adamc AT csail.mit.edu>
- To: Vincent Siles <vincent.siles AT ens-lyon.org>
- Cc: Coq Club <coq-club AT inria.fr>, j.alglave AT ucl.ac.uk
- Subject: Re: [Coq-Club] not_ex_all_not seems to have trouble with multiple identifiers
- Date: Sun, 14 Oct 2012 11:55:26 -0400
On 10/14/2012 11:51 AM, Vincent Siles wrote:
Using the lemma of Classical_Pred_Set.v, Lemma not_ex_all_not : forall P:U -> Prop, ~ (exists n : U, P n) -> forall n:U, ~ P n.
I wanted to prove (a more complicated lemma but it boils down to)
Lemma foo (A:Set) (P : A -> Prop) : ~(exists x, exists y, exists z, (P x /\ P y /\ P z)) -> forall x y z, ~(P x /\ P y /\ P z).
Perhaps your question is more about specific low-level tactics than about the best way to prove your examples, but I'll just point out that the built-in [firstorder] tactic proves either of these facts automatically, without appealing to axioms.
- [Coq-Club] not_ex_all_not seems to have trouble with multiple identifiers, Vincent Siles, 10/14/2012
- Re: [Coq-Club] not_ex_all_not seems to have trouble with multiple identifiers, Adam Chlipala, 10/14/2012
- Re: [Coq-Club] not_ex_all_not seems to have trouble with multiple identifiers, Vincent Siles, 10/15/2012
- Re: [Coq-Club] not_ex_all_not seems to have trouble with multiple identifiers, Adam Chlipala, 10/14/2012
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