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- From: Kevin Sullivan <sullivan.kevinj AT gmail.com>
- To: Freek Wiedijk <freek AT cs.ru.nl>
- Cc: Gabriel Scherer <gabriel.scherer AT gmail.com>, "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: Re: [Coq-Club] Sum of all nats = 1/12
- Date: Tue, 4 Feb 2014 06:58:08 -0500
Right, it just relies on a non-standard definition of sum, see also Grandi series.
A colleague also wrote, :"One can also consider it as an example of analytic continuation. For example if z is not equal to 1 then 1/(1-z) = 1+z+z^2+.... The series on the right converges if |z|<1 with |z|=1 as a natural barrier. Both sides agree (yield the same value) and are analytic if |z|<1. But the left side is exists and is analytic for all z not equal to 1. Therefore, the left side is the analytic continuation of the right side and hence can be used to assign a value to the infinite series on the right in regions where it does not converge." Mystery resolved.
- [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/03/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/03/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/03/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Marco Servetto, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/03/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Gabriel Scherer, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Freek Wiedijk, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Frédéric Chyzak, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Freek Wiedijk, 02/04/2014
- Re: [Coq-Club] Sum of all nats = 1/12, Kevin Sullivan, 02/03/2014
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