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- From: yasu AT yasuaki.com
- To: Coq Club <coq-club AT inria.fr>
- Subject: [Coq-Club] Very basic question of < and <=
- Date: Mon, 13 Jul 2015 07:59:04 +0900
Hi,
I am a beginner - why is the proof below ok? I understand semantically this is trivial, but what is the mechanism of H to S a <= b ?
Theorem T: forall a b:nat, a < b -> S a <= b.
Proof .
intros .
exact H .
Qed.
Print T.
Cheers,
Yasuaki
- [Coq-Club] Very basic question of < and <=, yasu, 07/13/2015
- Re: [Coq-Club] Very basic question of < and <=, roux cody, 07/13/2015
- Re: [Coq-Club] Very basic question of < and <=, yasu, 07/13/2015
- Re: [Coq-Club] Very basic question of < and <=, roux cody, 07/13/2015
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