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- From: richard dapoigny <richard.dapoigny AT univ-smb.fr>
- To: coq-club AT inria.fr
- Subject: [Coq-Club] Coercions with constructors of inductive types
- Date: Fri, 21 Oct 2016 22:47:08 +0200
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Dear all, I read in the Coq doc that
inductive types may admit coercions within their constructor (see
https://coq.inria.fr/refman/Reference-Manual021.html#sec657).
However, when I try it, i get an error: Error: The type of constructor es is not valid; it must be "EpsilonStarL" applied to its parameters. I forward the code below. Thanks for your help. Richard ========================================= Inductive Name : Type := | bottom : Name | top : Name | name : Name | unaryF : Name -> Name | binaryF : Name -> Name -> Name | ternaryF : Name -> Name -> Name -> Name. Inductive NS : Type := ns : NS. Inductive NP : Type := np : NP. Inductive NE : Type := ne : NE. Variable cs : NS -> Name. Variable cp : NP -> Name. Variable ce : NE -> Name. Coercion cs : NS >-> Name. Coercion cp : NP >-> Name. Coercion ce : NE >-> Name. Definition star (a:Name)(A:NS) := binaryF a A. Inductive Epsilon (A :NS) (b:Name) : Prop := epsilon : Epsilon A b. Inductive EpsilonStarL (A B:NS) (b:Name) : Prop := es :> Epsilon A (star b B). |
- [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, Fabian Kunze, 10/20/2016
- Re: [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, John Wiegley, 10/20/2016
- Re: [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, Fabian Kunze, 10/21/2016
- [Coq-Club] Coercions with constructors of inductive types, richard dapoigny, 10/21/2016
- Re: [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, Matthieu Sozeau, 10/23/2016
- Re: [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, Fabian Kunze, 10/21/2016
- Re: [Coq-Club] Setoid Rewrite with non-transitive (step-indexed) Relations, John Wiegley, 10/20/2016
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