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- From: Pierre Courtieu <pierre.courtieu AT gmail.com>
- To: Coq Club <coq-club AT inria.fr>
- Subject: Re: [Coq-Club] typeclass resolution and unfold
- Date: Thu, 6 Jul 2017 17:37:54 +0200
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Hi Julien,
I usually use tactic notation to deal with names like this:
Tactic Notation "myunfold" reference(x) := (unfold x).
Best regards,
Pierre
2017-07-06 17:12 GMT+02:00 Julien Narboux <jnarboux AT narboux.fr>:
Hello,I have defined a type class, and definitions depending on fields of the type class.I would like to write a tactic which unfold the definition given as an argument.How can I do that ?Here is a small test case:Class foo:= {A : Type;B: A -> A -> Prop;babar a b := B a b /\ B b a;}.Ltac myunfold t := unfold t.Section bar.Context `{Ax:foo}.Lemma titi : forall a b, babar a b.Proof.intros.(* unfold babar. works *)myunfold babar.(* In nested Ltac calls to "myunfold" and "unfold t", last call failed.Error: Ltac variable t is bound to babar which cannot be coerced toan evaluable reference. *)Julien
- [Coq-Club] typeclass resolution and unfold, Julien Narboux, 07/06/2017
- Re: [Coq-Club] typeclass resolution and unfold, Pierre Courtieu, 07/06/2017
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