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- From: Gregory Malecha <gregory AT bedrocksystems.com>
- To: coq-club AT inria.fr
- Subject: Re: [Coq-Club] Question
- Date: Sun, 6 Sep 2020 22:42:31 -0400
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Dear Coq users,
I have the following problem with the code fragment:
Record object : Type := {
ob_class : Type;
ob : ob_class}.
Class Lives : Type := {
n01 : nationalities;
h01 : house;
pr01 : lives h01 = n01
}.
Class hasColor : Type := {
h02 : house;
c01 : color;
pr03 : Color c01 = h02
}.
Hypothesis A001 : forall (x:hasColor)(y:Lives)(Xob:object), @ob_class Xob = house /\ @h02 x = @ob Xob /\ Color Red = (@h02 x) /\ lives (@h02 x) = Englishman.
I get the following error: Illegal application (Non-functional construction):
The _expression_ "ob" of type "house" cannot be applied to the term "Xob" : "object"The problem is that the type of @ob Xob is @ob_class Xob which is equal to house from the first assertion. The second assertion cannot take this assertion in account. So the question is: is there a way to overcome this behavior?
Thanks in advance for your answer,
Richard
--
Richard Dapoigny
Associate Professor - LISTIC Laboratory
University Savoie Mont-Blanc
5, chemin de Bellevue
Po. Box 80439
Annecy-le-Vieux 74940
FRANCE
https://www.listic.univ-smb.fr/en/presentation-en/members/lecturers/richard-dapoigny-en/
****** People who don't know history are condemned to repeat it. ******
--
Gregory Malecha
Mail: gregory AT bedrocksystems.com
BedRock
Systems Inc
UNBREAKABLE FOUNDATION
FOR
- [Coq-Club] Question, richard Dapoigny, 09/06/2020
- Re: [Coq-Club] Question, Gregory Malecha, 09/07/2020
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