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- From: Laurent Théry <>
- To:
- Subject: Re: Bijection of vector spaces
- Date: Thu, 03 May 2012 16:22:33 +0200
Opps I am wrong this is not so simple, so maybe Cyril solution is a more direct one.
I thought the function f that I was defining was not linear over the whole space but it is
Lemma f_is_linear : linear f.
Proof.
move=> k x y; rewrite /f scaler_sumr -big_split /=.
by apply: eq_bigr=> i _; rewrite linearD linearZ scalerDl scalerA.
Qed.
So it is restriction to V1 is an isomorphism.
--
Laurent
- Bijection of vector spaces, Anders, 05/02/2012
- Re: Bijection of vector spaces, Vincent Siles, 05/03/2012
- Message not available
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Message not available
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Re: Bijection of vector spaces, Vincent Siles, 05/03/2012
- Re: Bijection of vector spaces, Cyril Cohen, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- RE: Bijection of vector spaces, Georges Gonthier, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- RE: Bijection of vector spaces, Georges Gonthier, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
- Re: Bijection of vector spaces, Laurent Théry, 05/03/2012
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