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Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?
Chronological Thread
- From: Jason Gross <>
- To: Enrico Tassi <>
- Cc: ssreflect <>
- Subject: Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?
- Date: Thu, 26 Jun 2014 17:01:09 +0100
Indeed, that helps.
I'm trying to have [case], but only when the term being cased unifies with [and _ _]. I was hoping for something like
do ![ case/(@id (ex _))
| case/(@id (and _ _))
| move => ? ]
to intro everything, destructing anything of type [ex _] or [and _ _] along the way.
-Jason
On Thu, Jun 26, 2014 at 4:49 PM, Enrico Tassi <> wrote:
On Thu, Jun 26, 2014 at 04:34:27PM +0100, Jason Gross wrote:I hope that this decompilation helps you understand what goes wrong:
> Hi,
> The following code fails with "Error: Not an inductive product":
>
> Require Import ssreflect. (* v 1.4 *)
> Goal forall A B, A /\ B -> True.
> move => A B.
> case/(@id (and _ _)).
have xx := @id (and _ _).
Goal forall A B, A /\ B -> True.
move => A B.
move/xx.
case.
Given that "xx : forall P P0 : Prop, P /\ P0 -> P /\ P0", the first
premise "A /\ B" can play the role of P, being of type Prop.
But the real question is: what are you trying to do?
Best,
--
Enrico Tassi
- [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Jason Gross, 06/26/2014
- Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Enrico Tassi, 06/26/2014
- Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Jason Gross, 06/26/2014
- Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Enrico Tassi, 06/26/2014
- RE: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Georges Gonthier, 06/26/2014
- Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Jason Gross, 06/26/2014
- Re: [ssreflect] Why does [case/(@id (and _ _))] tell me that [and] is not an inductive product?, Enrico Tassi, 06/26/2014
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