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- From: Christoph Weber <>
- To:
- Subject: Re: [cgal-discuss] I need your help
- Date: Tue, 17 Mar 2009 17:09:48 +0100
hi Alexa,
Triangulation_3 means, that your Points are in the 3 dimensional space.
So instead of triangles you have tetraeders. For the representation of a
tetraeder you need 4 vertices.
reg, christoph
Am Dienstag, den 17.03.2009, 07:18 -0700 schrieb alexa alexandra:
> hello...I saw that you worked with delaunay triangulation...Please
> help me....
> I compiled the simple_triangulation_3 and I dont understand why it
> gives me 4 point for triangulation in output...
> 16
> 200 200 0
> 0 0 0
> 200 0 0
> 0 200 0
> 0 0 50
> 0 0 100
> 0 0 150
> 0 200 150
> 0 200 100
> 0 200 50
> 200 200 50
> 200 200 100
> 200 200 150
> 200 0 150
> 200 0 100
> 200 0 50
> 46
> 7 1 3 6
> 1 2 3 5
> 2 0 3 5
> 1 3 2 0
> 4 2 1 5
> 8 11 0 12
> 4 0 2 5
> 4 1 2 0
> 0 11 3 12
> 10 9 0 7
> 6 1 3 5
> 0 6 3 5
> 4 6 0 5
> 4 1 6 5
> 0 7 3 6
>
> All I want for this program is the coords of triangulation.Which
> points form a triangle.
> I tried to compile your program newTestAgain...but I don't have the 2
> headers mex.h and find_surface_normal.h.Can you send me pls....
>
>
- [cgal-discuss] I need your help, alexa alexandra, 03/17/2009
- Re: [cgal-discuss] I need your help, Christoph Weber, 03/17/2009
- [cgal-discuss] cgal parabola plot, Khuong Vu, 03/17/2009
- Re: [cgal-discuss] I need your help, alexa alexandra, 03/21/2009
- Re: [cgal-discuss] I need your help, Monique Teillaud, 03/23/2009
- Re: [cgal-discuss] I need your help, Christoph Weber, 03/17/2009
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