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Re: [cgal-discuss] Re: polygon triangulation


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  • From: sara Samadi <>
  • To:
  • Subject: Re: [cgal-discuss] Re: polygon triangulation
  • Date: Tue, 19 Apr 2011 00:43:49 -0700 (PDT)
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Thanks for your help,
 
sorry, i cant understand the concept of "propagation from triangles to triangles", is it possible for you to explain it little clearer?
 
Thanks in advance.

--- On Thu, 4/14/11, Sebastien Loriot (GeometryFactory) <> wrote:

From: Sebastien Loriot (GeometryFactory) <>
Subject: Re: [cgal-discuss] Re: polygon triangulation
To:
Date: Thursday, April 14, 2011, 6:59 AM

On 04/14/2011 05:32 AM, sara123 wrote:
> After reading the cgal manual (2D Triangulations) I realized that after
> constrained triangulation of a simple polygon we have eventually a convex
> polygon, even if our input polygon does'nt be convex!

Of course, it is computing a triangulation of the plane.
You have to filter out triangles that are outside you original polygon.

You can use a propagation from triangles to triangles, never crossing a
constrained edge. The simplest is to start with an infinite face and
get all faces that are not in the polygon.

S.



>
> what should i do if i want this does'nt happen?
>
>
> --
> View this message in context: http://cgal-discuss.949826.n4.nabble.com/polygon-triangulation-tp3356157p3448688.html
> Sent from the cgal-discuss mailing list archive at Nabble.com.
>


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