CGAL users discussion list

[Michael Kalygin <>]

Alessandro, ah, I see.
To get a spherical triangle using triangulation's triangle you can build geodesic lines:

http://en.wikipedia.org/wiki/Geodesic

You can put one dummy point in the center of the sphere and then build 3D triangulation of your set of points (with this dummy point). I'm assuming that all your points belong to the sphere except the dummy point. This will give you a polyhedron. And then for each edge of the polyhedron you can build a geodesic line. Hope this will help you.

Thanks.

Michael.

On Fri, Jun 28, 2013 at 8:33 PM, isscandar [via cgal-discuss] <[hidden email]> wrote:

Michael Kalygin wrote

Hi, isscandar, I understand that CGAL has a huge manual. I started from
these sections. If you read them, you will understand how to work with
triangulation. Take a look at examples too.
http://www.cgal.org/Manual/3.2/doc_html/cgal_manual/Triangulation_3/Chapter_main.html
http://www.cgal.org/Manual/latest/doc_html/cgal_manual/TriangulationDS_3_ref/Concept_TriangulationDataStructure_3.html
http://www.cgal.org/Manual/latest/doc_html/cgal_manual/Triangulation_3_ref/Class_Triangulation_3.html

Hello Michael,
thank you very much for your help!
I have read some of the manual but I am still confused: quoting from the manual The class Triangulation_3 represents a 3-dimensional tetrahedralization of points. but I think I do not need tetrahedrons in the space because I think I need spherical triangle (http://mathworld.wolfram.com/SphericalTriangle.html), it is not clear to me whether I can get the spherical triangle from the tetrahedrons. What am I missing?

Alessandro

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Best regards,
Michael Kalygin.

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