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Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?
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- From: "Sebastien Loriot (GeometryFactory)" <>
- To:
- Subject: Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?
- Date: Wed, 12 Feb 2020 10:56:45 +0100
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The two pictures are the same.
Sebastien.
On 2/12/20 10:49 AM, Frank Dz wrote:
Hi, I want to ask is there a method for us to slice a mesh by setting a set
of points (or: a loop/ a set of edges) and have a connectivity check on the
mesh.
For example, the following loop cut the mesh, yet the connectivity is still
1.
<http://cgal-discuss.949826.n4.nabble.com/file/t376165/snapshot00.png>
Another example is the following that two loops cut the mesh and the
connectivity is 2.
<http://cgal-discuss.949826.n4.nabble.com/file/t376165/snapshot00.png>
Best,
Frank
-----
be open, be creative, be critical
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Sent from: http://cgal-discuss.949826.n4.nabble.com/
- [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Sebastien Loriot (GeometryFactory), 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Sebastien Loriot (GeometryFactory), 02/18/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/18/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Sebastien Loriot (GeometryFactory), 02/18/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Frank Dz, 02/12/2020
- Re: [cgal-discuss] CGAL Is there a way to slice the mesh and check the connectivity?, Sebastien Loriot (GeometryFactory), 02/12/2020
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