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- From: "Alessandro Warth" <alexwarth AT gmail.com>
- To: coq-club AT pauillac.inria.fr
- Subject: [Coq-Club]help with simple proof
- Date: Tue, 30 May 2006 17:04:35 -0700
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Hello,
I'm trying to use Coq to formalize a programming language that I've
been working on. Unfortunately, a few days ago I ran into trouble
while proving what (I think) should be a very simple lemma. I've spent
the past few days banging my head against the wall and have made no
progress, so I was hoping someone might be able to give me a few
pointers...
Here is the simplest formulation of that lemma that I could come up with:
Inductive AType : Set :=
| Red : nat -> AType
| Black : nat -> AType.
Inductive subtyping : AType -> AType -> Prop :=
| s_refl : forall T,
subtyping T T
| s_trans : forall T1 T2 T3,
subtyping T1 T2 ->
subtyping T2 T3 ->
subtyping T1 T3.
Lemma l : forall (n:nat) (T:AType),
subtyping (Red n) T ->
exists m:nat, T = (Red m).
This should be easy to prove, but I haven't had any luck so far. Does
anybody have any ideas about how I might be able to prove this?
Thank you kindly,
Alex Warth
- [Coq-Club]help with simple proof, Alessandro Warth
- Re: [Coq-Club]help with simple proof,
Pierre Letouzey
- Re: [Coq-Club]help with simple proof, Alessandro Warth
- Re: [Coq-Club]help with simple proof, Houda Anoun
- Re: [Coq-Club]help with simple proof, Pierre Casteran
- Re: [Coq-Club]help with simple proof,
Pierre Letouzey
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