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Re: [Coq-Club] Without law-of-excluded-middles, do we need a hierarchy of Types?


Chronological Thread 
  • From: "J. Ian Johnson" <ianj AT ccs.neu.edu>
  • To: t x <txrev319 AT gmail.com>
  • Cc: coq-club <coq-club AT inria.fr>
  • Subject: Re: [Coq-Club] Without law-of-excluded-middles, do we need a hierarchy of Types?
  • Date: Mon, 28 Oct 2013 11:06:45 -0400 (EDT)

Girard's paradox arises when you don't have predicativity.

http://plato.stanford.edu/entries/type-theory/

-Ian
----- Original Message -----
From: "t x"
<txrev319 AT gmail.com>
To: "coq-club"
<coq-club AT inria.fr>
Sent: Monday, October 28, 2013 11:02:52 AM GMT -05:00 US/Canada Eastern
Subject: [Coq-Club] Without law-of-excluded-middles, do we need a hierarchy
of Types?


Definitions (in case the true meaning of a word is different from my
understanding of it)





Law of excluded-middles:
forall (P: Prop), P \/ (P -> False)


Hierarchy of Types:
type_of(nat) = Type0
type_of(Type0) = Type1
type_of(Type1) = Type2
...


Paradox with "sets of sets":
X = { s | s \not\in s }




In classical logic, there's the argument:
does X \in X?
if yes, then X \not\in X, contradiction
if not, then X \in X, contradiction


However, in constructive logic, since we don't have the law of excluded
middles, it could just be that for "P = X \in X?", we can neither prove P nor
prove (P -> False).




Thus, my question: why does Coq have a hierarchy of Types?


Thanks!



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