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- From: Marcus Ramos <marcus.ramos AT univasf.edu.br>
- To: "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: Re: [Coq-Club] Why does this "apply in" does not work ?
- Date: Thu, 26 Jun 2014 12:22:25 +0200
Hi Vincent,
That was me, thanks for forwarding the question. As I had not seen your message before, I made another post with the same contents a few minutes ago. Sorry for the duplicate.
Marcus.
2014-06-26 12:00 GMT+02:00 Vincent Siles <vincent.siles AT ens-lyon.org>:
Hi club,
an interesting question was asked on StackOverflow yesterday, and I
have to say I don't understand why this simple apply fails. Consider
the script:
Parameter P: nat -> Prop.
Parameter Q: nat -> Prop.
Hypothesis x : forall i, P i -> (forall k, Q k).
Lemma y:
forall i, P i -> (* Whatever *) P i.
Proof.
intros i hPi.
apply x in hPi.
It fails with: Error: Unable to find an instance for the variable k.
Why does Coq asks for the instantiation of k ?
Best,
V.
- [Coq-Club] Why does this "apply in" does not work ?, Vincent Siles, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Marcus Ramos, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Gregory Malecha, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Marcus Ramos, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Gregory Malecha, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Jonathan, 06/26/2014
- Re: [Coq-Club] Why does this "apply in" does not work ?, Marcus Ramos, 06/26/2014
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