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- From: Bahman Sistany <bsistany AT yahoo.ca>
- To: Coq Club <coq-club AT inria.fr>
- Subject: [Coq-Club] How to refer to a un-destructed inductive types in Theorems
- Date: Wed, 22 Jul 2015 06:24:50 +0000 (UTC)
Hi,
I have a simple inductive type called 'constraint. Let's say in my context at some point I have:
a : constraint
b : constraint
The goal is some proposition isFree involving b. so:
a : constraint
b : constraint
H: isFree (a).
------------------------------------
isFree(b)
What am I missing from proving this simple goal given H? I know if I had 'a=b' in the context, it would be simple but I don't.
And proof-irrelevance applies to Props only otherwise it would have given me a=b.
In this case should I expect that isFree (a) implies isFree(b)?
--Bahman
- [Coq-Club] How to refer to a un-destructed inductive types in Theorems, Bahman Sistany, 07/22/2015
- Re: [Coq-Club] How to refer to a un-destructed inductive types in Theorems, Gabriel Scherer, 07/22/2015
- Re: [Coq-Club] How to refer to a un-destructed inductive types in Theorems, Cedric Auger, 07/22/2015
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