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[Coq-Club] fun <-> forall


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  • From: Burak Ekici <ekcburak AT hotmail.com>
  • To: Coq Club <coq-club AT inria.fr>
  • Subject: [Coq-Club] fun <-> forall
  • Date: Thu, 26 Oct 2017 11:09:12 +0000
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Hi all,

I have an hypothesis of the following form "H : (fun a b f => XX a b f)
= (fun a b f => YY a b f)".

Is there a way to turn it into "H: forall a b f, XX a b f = YY a b f"?

Thanks!

Best,



Burak.






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