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- From: Thorsten Altenkirch <Thorsten.Altenkirch AT nottingham.ac.uk>
- To: "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: Re: [Coq-Club] Variable closure
- Date: Sun, 12 May 2019 15:46:18 +0000
- Accept-language: en-US
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If you replace “forall y,F” by “exists y, F” it even holds intuitionistically. In the present form it is false, even classically.
From:
<coq-club-request AT inria.fr> on behalf of richard Dapoigny <richard.dapoigny AT univ-smb.fr>
Dear all, using classical logic in Coq, is there a way to prove that the following equivalence holds? forall x, ((forall y, F) -> G) <-> forall x y, (F -> G) in which F depends on x an y while G only depends on x Thanks for your answer, Rich -- This message and any attachment are intended solely for the addressee and may contain confidential information. If you have received this message in error, please contact the sender and delete the email and attachment. Any views or opinions expressed by the author of this email do not necessarily reflect the views of the University of Nottingham. Email communications with the University of Nottingham may be monitored where permitted by law. |
- [Coq-Club] Variable closure, richard Dapoigny, 05/12/2019
- Re: [Coq-Club] Variable closure, Arthur Azevedo de Amorim, 05/12/2019
- Re: [Coq-Club] Variable closure, Jeremy Dawson, 05/12/2019
- Re: [Coq-Club] Variable closure, richard Dapoigny, 05/12/2019
- Re: [Coq-Club] Variable closure, Tadeusz Litak, 05/12/2019
- Re: [Coq-Club] Variable closure, Kenji Maillard, 05/12/2019
- Re: [Coq-Club] Variable closure, Tadeusz Litak, 05/12/2019
- Re: [Coq-Club] Variable closure, richard Dapoigny, 05/12/2019
- Re: [Coq-Club] Variable closure, Thorsten Altenkirch, 05/12/2019
- Re: [Coq-Club] Variable closure, Michel Levy, 05/12/2019
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