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Re: [cgal-discuss] external vertexes in a triangulation


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  • From: "Sebastien Loriot (GeometryFactory)" <>
  • To:
  • Subject: Re: [cgal-discuss] external vertexes in a triangulation
  • Date: Mon, 30 Jan 2012 15:58:22 +0100

What is your definition of external vertices?

Sebastien.

On 01/30/2012 03:41 PM, Adam Hopkins wrote:
Hi Daniel:

Thank you for your help, but I think that it is not the correct way to
solve my problem. When the convex hull is computed not all the external
vertexes are included. For this reason, I need other form to know which
are the real external vertexes of a triangulation.

Regards and waiting more suggestions
A.

On Mon, Jan 30, 2012 at 3:29 PM, Daniel Duque
<
<mailto:>>
wrote:

On Monday 30 January 2012 15:20:52 Adam Hopkins wrote:
> Hi all,
>
> Thank you for your previous answers, but I have a last issue
related with
> triangulations.
>
> Using the example code below, I can know which are the external
cells of a
> triangulations, but I also need to know which are the external
vertex of
> the same triangulation.

I guess you mean the vertices that form the convex hull. Have a look
here:


http://www.cgal.org/Manual/latest/doc_html/cgal_manual/Triangulation_2/Chapter_main.html#Subsection_36.4.2

Best,

Daniel


> Is there any form to know which are the external
> facets of each of these cells in order to know which are the most
external
> vertexes of this triangulation?
>
> Concretely, How Can I know which are the external vertices of a
> triangulation?
>
> std::vector<Cell_handle> infinite_cells;
> T.incident_cells(T.infinite_vertex(),
std::back_inserter(infinite_cells));
>
> for(int ii = 0; ii < (int)infinite_cells.size(); ii++)
> {
> Cell_handle c = infinite_cells[ii];
> Cell_handle e = c->neighbor(c->index(T.infinite_vertex()));
> }
>
> Regards and thank you for all
> A.

--
http://dcain.etsin.upm.es/~daniel

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