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- From: Zohar <>
- To:
- Subject: [cgal-discuss] Re: Triangulation_3 and C3t3 questions
- Date: Mon, 16 Jul 2012 04:26:15 -0700 (PDT)
Yes, I could also hold a map from cell handle to boolean value, or other
creative stuff, but it's all sound too cumbersome, and adds a complexity for
algorithms that use it. I wouldn't be able for example to extract the
surface by simply iterating the faces of the infinite cell. Also when I add
points to the triangulation, some of the marked tets would decide to split
or something, and I would lose the marking. So the easiest solution I see so
far is:
1. Generate a triangulation T1 using c3t3.
2. Construct with the points of T1 a new delaunay triangulation 3, T2.
3. Add some new points to T2 (could be inside or outside of T1 shape).
4. Copy T2 to a standard triangulation 3, T3.
5. Remove cells from T3, whose center isn't in T1 and don't have one of the
points from 3 as an ear...
6. Work with T3, and if there's a need to change the triangulation repeat a
similar process ...
and better ideas would be welcomed.
--
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- [cgal-discuss] Triangulation_3 and C3t3 questions, Zohar, 07/14/2012
- Re: [cgal-discuss] Triangulation_3 and C3t3 questions, Mariette Yvinec, 07/16/2012
- [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Zohar, 07/16/2012
- Re: [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Mariette Yvinec, 07/16/2012
- Re: [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Monique Teillaud, 07/16/2012
- [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Zohar, 07/16/2012
- Re: [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Monique Teillaud, 07/16/2012
- [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Zohar, 07/16/2012
- Re: [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Monique Teillaud, 07/16/2012
- Re: [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Mariette Yvinec, 07/16/2012
- [cgal-discuss] Re: Triangulation_3 and C3t3 questions, Zohar, 07/16/2012
- Re: [cgal-discuss] Triangulation_3 and C3t3 questions, Mariette Yvinec, 07/16/2012
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