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- From: Winnie <>
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- Subject: [cgal-discuss] constrained triangulation existance
- Date: Mon, 03 Jun 2013 20:48:30 +0200
Hi list,
if I understand it right, the CGAL implementation claims to find a constrained triangulation in polynomial time [1]. Given that the constraints don't intersect, does this also claim that there always exists a triangulation?
If I understand Lloyd [2] [3] right, he claims that the decision whether a constrained triangulation exists (he calls it TRI) is already NP-complete.
But... if I can find a constrained triangulation in polynomial time, wouldn't that also solve the decision problem whether there exists a triangulation?
I hope somebody of you can help me out of this. Thanks in advance!
Winnie
[1] http://www.cgal.org/Manual/latest/doc_html/cgal_manual/Triangulation_2_ref/Class_Constrained_triangulation_2.html#Function_void_insert_constraint6Point_a+_Point_b9;
[2] http://ieeexplore.ieee.org/xpls/abs_all.jsp?arnumber=4567947
[3] https://www.math.ucdavis.edu/~deloera/MISC/BIBLIOTECA/trunk/Lloyd.pdf
- [cgal-discuss] constrained triangulation existance, Winnie, 06/03/2013
- Re: [cgal-discuss] constrained triangulation existance, Laurent Rineau (CGAL/GeometryFactory), 06/04/2013
- Re: [cgal-discuss] constrained triangulation existance, Winnie, 06/06/2013
- Re: [cgal-discuss] constrained triangulation existance, Laurent Rineau (CGAL/GeometryFactory), 06/04/2013
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