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Re: [cgal-discuss] Intersection between Delaunay triangulations


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  • From: Thiago Milanetto Schlittler <>
  • To:
  • Subject: Re: [cgal-discuss] Intersection between Delaunay triangulations
  • Date: Sun, 27 Nov 2016 00:20:24 +0100
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Hello!

   Just one question: are these 2D / surface mesh triangulations, with triangular cells, or 3D triangulations with tetrahedral cells? I've had to do something similar for my work for the 3D triangulations, and ended up using the second option: converting the cells to Nef_Polyhedrons and then obtaining their intersections. This works well, is very easy to code, and is easily adaptable to meshes with hexahedral or mixed cell types, but it's a bit expensive on time. If you already have the list of intersecting cells beforehand, this is not a big problem, though.

   For the 2D triangulations, I think that you can use the 2D Nef polygons module to do something similar, but I have no ideas of how to do it for surface meshes.

Thiago

2016-11-26 4:36 GMT+01:00 pbarletta <>:
Hi,
      I have 2 triangulations (A and B) and I would like to compute the
volume of the intersections between triangulation *A* and some cells of
triangulation *B*. These intersecting cells are only a few.
      The 3 cases are possible:
            1 vertex of the cell is inside the triangulation *A*.
            2 vertices of the cell is inside the triangulation *A*.
            3 vertices of the cell is inside the triangulation *A*.

      I'm wondering what would be the best approach:

         -- Computing the intersection points to construct new polyhedrons
and then calculate their volume?
         -- Converting the intersecting cells (and the triangulation *A*) to
Nef_Polyhedrons and then obtain the intersection, which may be converted
back to a polyhedron to calculate its volume?
         -- Any other option I'm not thinking of?

    I started off with the 1st option, but since CGAL::intersection() does
not take cells as inputs, and there is the chance that the intersecting cell
traverse more than 1 cell of the triangulation *A*, I started doubting.

Any help is appreciated.




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