Subject: CGAL users discussion list
List archive
- From: pbarletta <>
- To:
- Subject: [cgal-discuss] Intersection between Delaunay triangulations
- Date: Fri, 25 Nov 2016 19:36:09 -0800 (PST)
- Authentication-results: mail3-smtp-sop.national.inria.fr; spf=None ; spf=SoftFail ; spf=None
- Ironport-phdr: 9a23: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
Hi,
I have 2 triangulations (A and B) and I would like to compute the
volume of the intersections between triangulation *A* and some cells of
triangulation *B*. These intersecting cells are only a few.
The 3 cases are possible:
1 vertex of the cell is inside the triangulation *A*.
2 vertices of the cell is inside the triangulation *A*.
3 vertices of the cell is inside the triangulation *A*.
I'm wondering what would be the best approach:
-- Computing the intersection points to construct new polyhedrons
and then calculate their volume?
-- Converting the intersecting cells (and the triangulation *A*) to
Nef_Polyhedrons and then obtain the intersection, which may be converted
back to a polyhedron to calculate its volume?
-- Any other option I'm not thinking of?
I started off with the 1st option, but since CGAL::intersection() does
not take cells as inputs, and there is the chance that the intersecting cell
traverse more than 1 cell of the triangulation *A*, I started doubting.
Any help is appreciated.
--
View this message in context:
http://cgal-discuss.949826.n4.nabble.com/Intersection-between-Delaunay-triangulations-tp4662395.html
Sent from the cgal-discuss mailing list archive at Nabble.com.
- [cgal-discuss] Intersection between Delaunay triangulations, pbarletta, 11/26/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, Thiago Milanetto Schlittler, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, pbarletta, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, Thiago Milanetto Schlittler, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, pbarletta, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, Thiago Milanetto Schlittler, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, pbarletta, 11/27/2016
- Re: [cgal-discuss] Intersection between Delaunay triangulations, Thiago Milanetto Schlittler, 11/27/2016
Archive powered by MHonArc 2.6.18.