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- From: Fabrice Lemercier <nouvid-coq AT yahoo.fr>
- To: coq-club AT pauillac.inria.fr
- Subject: [Coq-Club]Type system in Coq
- Date: Wed, 7 Jun 2006 03:16:07 +0200 (CEST)
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Hello,
I am formalizing a language and its type system in
Coq. Follow a simple example which is sufficient to
exhibit my problem.
The syntax of my language (consisting of just one
constant) is given by the following inductive
definition:
Inductive Trm : Set :=
trm : Trm.
There is only one typing rules (stating that my
constant is well typed) given by:
Inductive Typ : Trm->Set :=
axiom : Typ trm.
Now, I'd like to prove a fundamental property of my
type system which is that for each term there is a
unique type derivation:
Goal forall t:Trm, forall x y:Typ t, x=y.
I know that if I put Typ in Prop instead of Set, then
I can prove the above statement by using proof
irrelevance in classical logic. But I put them in Set
because I want them to be extracted. What can I do?
Thanks,
Fabrice
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- [Coq-Club]Type system in Coq, Fabrice Lemercier
- Re: [Coq-Club]Type system in Coq, Santiago Zanella Béguelin
- Re: [Coq-Club]Type system in Coq,
Lionel Elie Mamane
- RE : Re: [Coq-Club]Type system in Coq,
Fabrice Lemercier
- Re: RE : Re: [Coq-Club]Type system in Coq, Roland Zumkeller
- Re: RE : Re: [Coq-Club]Type system in Coq, Lionel Elie Mamane
- Re: RE : Re: [Coq-Club]Type system in Coq, Frederic Blanqui
- RE : Re: [Coq-Club]Type system in Coq,
Fabrice Lemercier
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