coq-club AT inria.fr
Subject: The Coq mailing list
List archive
- From: "Stefan O'Rear" <stefanor AT cox.net>
- To: Ethan Aubin <ethan.aubin AT gmail.com>
- Cc: coq-club AT pauillac.inria.fr
- Subject: Re: [Coq-Club] symmetric equality
- Date: Fri, 28 Sep 2007 21:36:10 -0700
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
On Sat, Sep 29, 2007 at 12:26:06AM -0400, Ethan Aubin wrote:
> Hi, This might be an obvious question, but is 'forall (A:Set)(x y:A),
> (x=y)=(y=x)' provable in Coq? - EA
Equality is a very slippery subject in Coq and other systems based on
intuitionistic type theories. Your statement is certainly true if you
replace the outer = with <-> (split; auto). In general, it's a bad idea
to use = on anything other than values of inductive types.
Stefan
Attachment:
signature.asc
Description: Digital signature
- [Coq-Club] symmetric equality, Ethan Aubin
- Re: [Coq-Club] symmetric equality, Stefan O'Rear
- Re: [Coq-Club] symmetric equality, vsiles
- Re: [Coq-Club] symmetric equality,
Sean Wilson
- Re: [Coq-Club] symmetric equality, Stefan O'Rear
- Re: [Coq-Club] symmetric equality, Stefan O'Rear
Archive powered by MhonArc 2.6.16.