coq-club AT inria.fr
Subject: The Coq mailing list
List archive
- From: Vincent Aravantinos <vincent.aravantinos AT gmail.com>
- To: gang chen <gangchen_sh AT yahoo.com>
- Cc: coq-club AT pauillac.inria.fr
- Subject: Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?
- Date: Thu, 14 Feb 2008 10:54:17 +0100
- Domainkey-signature: a=rsa-sha1; c=nofws; d=gmail.com; s=gamma; h=in-reply-to:references:mime-version:content-type:message-id:cc:content-transfer-encoding:subject:date:to:x-mailer:from; b=a9baeqkMhoExXOco/D9kP++hA7pOQeIEE9j8oa43SLhO5oXxEz0wt/1kcKdumpLGP6xADS73iNqNmT5fsidQ9QNshiEPStR+PYBTv9Zp0aO0rWi947tesb15O/xJv88ycf06rHkAxETwBdYCYNYLGmYB7ZncOvynhe/Wzk0o2+Y=
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
Le 14 févr. 08 à 00:17, gang chen a écrit :
More precisely, is the assertion
Goal equiv : forall (F : Prop->Prop) (A B : Prop),
(A<->B)->((F A)<->(F B)).
provable ?
I believe this conjecture is false without further restriction on F.
(I'm not a specialist so I'm not sure the following reasonning is ok. Many people on this list are more qualified than I am, so if I'm wrong we will know it quickly :)
Assume you are given two functions (f:Prop -> nat) and (g:nat -> Prop), and then define a F like this:
Definition F (P:Prop) : Prop -> Prop := g (1 + f P).
I don't see any reason why such a function would respect your conjecture.
Vincent
- [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?, gang chen
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?, Vincent Aravantinos
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Robin Green
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Vincent Aravantinos
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Gyesik Lee
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?, Andreas Abel
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?, Bruno Barras
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Gyesik Lee
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Vincent Aravantinos
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?,
Robin Green
- Re: [Coq-Club] is "(A<->B)->((F A)<->(F B))" provable ?, Vincent Aravantinos
Archive powered by MhonArc 2.6.16.