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- From: Benjamin Pierce <bcpierce AT cis.upenn.edu>
- To: coq-club AT pauillac.inria.fr
- Cc: Martin Hofmann <mhofmann AT TCS.IFI.LMU.DE>
- Subject: [Coq-Club] Strengthening the definitional equality on types?
- Date: Tue, 4 Aug 2009 17:24:15 -0400
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
Suppose one wanted to define isomorphisms in the following slightly unusual fashion:
Inductive Dir : Set := R | L.
Definition swap (d:Dir) := match d with R => L | L => R end.
Module Type Iso.
Parameter S : Dir -> Set.
Parameter f : forall d, S d -> S (swap d).
Axiom isoAx : forall d x, f (swap d) (f d x) = x.
End Iso.
Instead of two separate functions, two axioms, and two sets, we index everything by a direction. This means we can write definitions of composition of isomorphisms, juxtaposition, etc. and prove their properties very compactly (saving 50% of the typing each time).
Unfortunately, this definition doesn't typecheck: the term
f (swap d) (f d x)
has type S (swap (swap d)), not S d, which is the type of x. Of course, swap (swap d) is provably equal to d for every d, but not convertible.
What to do? We've seen the discussion of John Major equality in CoqArt... is this our only hope, or is there a lighter way?
Thanks!
- Benjamin Pierce and Martin Hofmann
- [Coq-Club] Strengthening the definitional equality on types?, Benjamin Pierce
- Re: [Coq-Club] Strengthening the definitional equality on types?, Adam Chlipala
- Re: [Coq-Club] Strengthening the definitional equality on types?, Arnaud Spiwack
- Re: [Coq-Club] Strengthening the definitional equality on types?, Arnaud Spiwack
- Re: [Coq-Club] Strengthening the definitional equality on types?, AUGER Cedric
- Re: [Coq-Club] Strengthening the definitional equality on types?, Stefan Monnier
- Re: [Coq-Club] Strengthening the definitional equality on types?, Conor McBride
- Re: [Coq-Club] Strengthening the definitional equality on types?, Hugo Herbelin
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