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- From: Bernard Hurley <bernard AT marcade.biz>
- To: "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: [Coq-Club] Equality of functions.
- Date: Wed, 25 Apr 2012 00:47:21 +0100
Hi all,
In the following scenario, is it possible to prove the Lemma?
+++++++++++++++++++++++++++
Section test.
Variables A B : Set.
Variables f g : A -> B.
Hypothesis Hyp1: forall a, f a = g a.
Lemma test : f = g.
End test.
+++++++++++++++++++++++++++
The hypothesis is just the normal mathematical definition of the
equality of two functions. But I can't figure out whether it is
reasonable to expect to be able to prove the Lemma or whether one would
need and extra axiom.
Thanks,
Bernard.
- [Coq-Club] Equality of functions., Bernard Hurley
- Re: [Coq-Club] Equality of functions.,
Adam Chlipala
- Re: [Coq-Club] Equality of functions.,
Bernard Hurley
- Re: [Coq-Club] Equality of functions., Jonas Oberhauser
- Re: [Coq-Club] Equality of functions.,
Bernard Hurley
- Re: [Coq-Club] Equality of functions., Kristopher Micinski
- Re: [Coq-Club] Equality of functions.,
Adam Chlipala
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