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Re: [Coq-Club] equality of equality of equality of equality


Chronological Thread 
  • From: Andrej Bauer <andrej.bauer AT andrej.com>
  • To: Vladimir Voevodsky <vladimir AT ias.edu>
  • Cc: Coq Club <coq-club AT inria.fr>
  • Subject: Re: [Coq-Club] equality of equality of equality of equality
  • Date: Fri, 18 May 2012 10:22:22 +0200

> Definition eqnplus1 ( n:nat ) {X : Type} ( x y : X) : Type.
> Proof. here follow the "destruct n" with eq X x y for n=0 and the obvious
> step for n+1. Defined.

The obvious step elludes me. Also, did you mean "destruct n" or "induction n"?

With kind regards,

Andrej



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