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- From: Math Prover <mathprover AT yahoo.com>
- To: "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: [Coq-Club]
- Date: Fri, 17 May 2013 18:36:03 -0700 (PDT)
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I'm using Coq 8.4 (downloaded from the main Coq website).
In the following block of code (also attached), I get an "Error: Cannot infer the implicit parameter Keq of assocList_r." error.
I believe what I have is a minimal example.
What confuses me is that:
* when I define it as part of a Function, I get an "Cannot infer the implicit parameter" error
1) Letting me know if there's anyway I can reformat my question to make it easier to answer. (Or any additional information I should provide.)
===== Code ======
Require Import List Coq.Classes.EquivDec.
Section assocList.
Variable K: Type.
Variable V: Type.
Variable Keq: forall k1 k2: K, {k1 = k2} + {k1 <> k2}.
Function assocList_r (lst: list (K * V)) (k: K) : option V :=
match lst with
| nil => None
| (k',v') :: xs =>
if Keq k k' then Some v' else assocList_r xs k
end.
End assocList.
Implicit Arguments assocList_r [K V Keq].
Definition lst1 := (1,2)::nil.
Check (assocList_r lst1 1).
(* Up until this line, all works *)
(* The following line gives me the error:
Error: Cannot infer the implicit parameter Keq of assocList_r. *)
Function f (lst: list (nat * nat)) (k: nat) :=
assocList_r lst k.
Attachment:
test.v
Description: Binary data
- [Coq-Club], Math Prover, 05/18/2013
- Re: [Coq-Club], Jonas Oberhauser, 05/18/2013
- Re: [Coq-Club], Feró, 05/18/2013
- Re: [Coq-Club], Math Prover, 05/18/2013
- Re: [Coq-Club], Feró, 05/18/2013
- Re: [Coq-Club], AUGER Cédric, 05/18/2013
- Re: [Coq-Club] Infer Implicit Type of KEq, Math Prover, 05/18/2013
- Re: [Coq-Club], Feró, 05/18/2013
- Re: [Coq-Club], Math Prover, 05/18/2013
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