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Re: [Coq-Club] how to prove and evaluate new function definition with this axioms
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- From: Mandy Martino <tesleft AT hotmail.com>
- To: "coq-club AT inria.fr" <coq-club AT inria.fr>
- Subject: Re: [Coq-Club] how to prove and evaluate new function definition with this axioms
- Date: Sun, 7 Feb 2016 08:00:04 +0000
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Hi ,
Is it possible to apply ring homomorphism on list to apply to axioms to auto generate recursive function or fixed point definition in coq?
Regards,
Martin
From: coq-club-request AT inria.fr <coq-club-request AT inria.fr> on behalf of Mandy Martino <tesleft AT hotmail.com>
Sent: Sunday, February 7, 2016 14:46
To: coq-club AT inria.fr
Subject: [Coq-Club] how to prove and evaluate new function definition with this axioms
Sent: Sunday, February 7, 2016 14:46
To: coq-club AT inria.fr
Subject: [Coq-Club] how to prove and evaluate new function definition with this axioms
Hi ,
Require Import Arith.
Parameter G : Type.
Axiom reflexive : forall x y z:G, x <= x.
Axiom symmetric : forall x y z:G, x = y <= y = x.
Axiom transitive : forall x y z:G, (z = y) * z <= (z = x) * x.
Regards,
Martin
- [Coq-Club] how to prove and evaluate new function definition with this axioms, Mandy Martino, 02/07/2016
- Re: [Coq-Club] how to prove and evaluate new function definition with this axioms, Mandy Martino, 02/07/2016
- Re: [Coq-Club] how to prove and evaluate new function definition with this axioms, Pierre Casteran, 02/07/2016
- Re: [Coq-Club] how to prove and evaluate new function definition with this axioms, Mandy Martino, 02/09/2016
- Re: [Coq-Club] how to prove and evaluate new function definition with this axioms, John Wiegley, 02/09/2016
- Re: [Coq-Club] how to prove and evaluate new function definition with this axioms, Mandy Martino, 02/09/2016
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