CGAL users discussion list

[Juan Carlos Lopez Alfonso <>]

Hi Oliver:

Thank you for your answer. But, maybe you dont understand my point.

How is possible that this points are not coplanar when the jacobian is exactly equal to 0? and you dont answer my question:  How Can I say to CGAL when computes the triangualtion that these points are coplanar?  at least with my criteria!!!

On the other hand, I cant include or remove points, and I need that the jacobian of each thetraedron is different to 0. I am using MS 10.0 and the jacobian is equal to 0, how is possible that in CGAL these points are not coplanar? I cant understand this issue.

In my code I will use the Jacobian and in some case some expressions are divide by the jacobian, and for this reason I need to have a jacobian different to 0, while in c++ the jacobian is 0 for CGAL is not.

Regards

Juan Carlos

On Fri, Jan 20, 2012 at 11:32 AM, Olivier Devillers <> wrote:

Le 1/20/12 11:13 AM, Juan Carlos Lopez Alfonso a écrit :

Hi There:

I have this concrete example:

..........

- How is possible that in CGAL these points are not coplanar? because these points are coplanar.

as already explained your points ARE NOT coplanar,
they are just almost coplanar (and since the volume is quite small you round it t zero)

- In order that I can't remove points, How Can I say to CGAL when computes the triangualtion that these points are coplanar?

THEY ARE NOT.
If you can compute another triangulation, but it will not be the Delaunay triangulation.

- I will use the resultant triangulation in other software where the jacobian is computed and I can't use the CGAL library. Is possible to change the CGAL test of coplanar points when the triangulation is computed?

if you cannot remove points, may be you can add (e.g. using the meshing package).

Olivier


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