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[Coq-Club]Is extensionality required ?


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  • From: "Eric Jaeger" <eric.jaeger AT sgdn.pm.gouv.fr>
  • To: <coq-club AT pauillac.inria.fr>
  • Subject: [Coq-Club]Is extensionality required ?
  • Date: Thu, 1 Feb 2007 21:55:48 +0100
  • List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
  • Organization: SGDN / DCSSI

Hi,

Is this result provable in Coq without additional axiom ?

Theorem f_abst:forall (dom ran:Set)(P:(dom->ran)->Prop)(f:dom->ran), P f->P (fun (d:dom)=>f d).

I mean, f and (fun (d:dom)=>f d) are more than extensionnally equal... What do you think ?

   Thanks for any help, Eric





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