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- From: <kwaxer AT mail.ru>
- To: coq-club AT inria.fr
- Subject: [Coq-Club] Question about proof with single negation and equality
- Date: Sun, 20 Jul 2014 21:39:34 +0200
Hi,
Given the following environment
Variable C: Set.
Variable N: Set.
Variable F: C-> N.
Axiom A: forall c c': C, (~ (c = c')) = (~ (F c = F c')).
how one can prove
Theorem T: forall (n: N) (c: С), F c = n -> forall c': C, F c' = n -> c = c'.
?
I believe this requires the proof of
Lemma L: forall A B: Prop, (~ A) = (~ B) -> A = B.
How can it be done? Can this be avoided as I guess the lemma requires
classical logic?
Thank you,
Alexander Kogtenkov
- [Coq-Club] Question about proof with single negation and equality, kwaxer, 07/20/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Jonathan, 07/20/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Cédric, 07/20/2014
- Re[2]: [Coq-Club] Question about proof with single negation and equality, Alexander Kogtenkov, 07/21/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Pierre Courtieu, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Cedric Auger, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Pierre Courtieu, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Cedric Auger, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Pierre Courtieu, 07/22/2014
- Re[2]: [Coq-Club] Question about proof with single negation and equality, Alexander Kogtenkov, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Arnaud Spiwack, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Cedric Auger, 07/22/2014
- Re: [Coq-Club] Question about proof with single negation and equality, Pierre Courtieu, 07/22/2014
- Re[2]: [Coq-Club] Question about proof with single negation and equality, Alexander Kogtenkov, 07/21/2014
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