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- From: emily_p <emilypurfield AT gmail.com>
- To: coq-club AT pauillac.inria.fr
- Subject: [Coq-Club] Proof Help
- Date: Sat, 11 Apr 2009 15:53:16 -0700 (PDT)
- List-archive: <http://pauillac.inria.fr/pipermail/coq-club/>
Hello,
I am fairly new to Coq and I am not sure if this is the right place to ask
but I am hoping someone can help me. I am having trouble with what I think
should be a simple proof. I am trying to solve the following
forall x, P x^Q x |- (forall x Px) ^(forall x Qx)
I have managed to solve the reverse of this but for this question I can't
seem to complete the proof. I can get to the stage where I have two subgoals
Px0 and Qx0 with the hypothesis forall x : S, Px^Qx but I am not sure how to
combine the goals to get a conjunction. I have used the following to get
this far but I may have gone down the wrong route completely.
intros. split. intro x0. 2: intro x0.
Thanks to anyone who can shed some light on this.
Emily
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- [Coq-Club] Proof Help, emily_p
- Re: [Coq-Club] Proof Help, Luke Palmer
- Re: [Coq-Club] Proof Help, muad
- <Possible follow-ups>
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fdabrows
- Re: [Coq-Club] Proof Help,
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- Re: [Coq-Club] Proof Help, fdabrows
- Re: [Coq-Club] Proof Help,
Roman Beslik
- Re: [Coq-Club] Proof Help,
Thomas Braibant
- Re: [Coq-Club] Proof Help, Adam Chlipala
- Re: [Coq-Club] Proof Help, Roman Beslik
- Re: [Coq-Club] Proof Help, Adam Chlipala
- Re: [Coq-Club] Proof Help,
Thomas Braibant
- Re: [Coq-Club] Proof Help,
Adam Chlipala
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